求下列微分方程满足所给初值条件的特解:-|||-(1) '=(e)^2x-y, |x=0;-|||-(2) cos xsin ydy=cos ysin xdx,y|x=0=dfrac (pi )(4);-|||-(3) 'sin x=yln y,y x=dfrac (pi )(2)=e;-|||-(4) cos ydx+(1+(e)^-x)sin ydy=0 |x=0=dfrac (pi )(4);-|||-(5) +2ydx=0,y|x=2=1.